n^2=30.25

Solution for n^2=30.25 equation:

n^2=30.25

We move all terms to the left:

n^2-(30.25)=0

We add all the numbers together, and all the variables

n^2-30.25=0

a = 1; b = 0; c = -30.25;
Δ = b2-4ac
Δ = 02-4·1·(-30.25)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-11}{2*1}=\frac{-11}{2}
=-5+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+11}{2*1}=\frac{11}{2}
=5+1/2
$